In an ap sum of first n terms is 3n 2/2
WebMar 27, 2024 · Solution For 10] Find the sum of first ' n ' terms of an AP 2 ,8 ,18 ,32 , 11] If α,β and γ are the zeroes of the polynomial P(x)=x3−6x2−x+30 then fin. The world’s only live instant tutoring platform. Become a tutor About us Student login Tutor login. Login. Student Tutor. Filo instant Ask button for chrome browser. ... WebThe sum of first n terms of an A.P is 5n−n 2. Find the n th term of this A.P A 6−5n B 6−2n C 5−2n D None of these Easy Solution Verified by Toppr Correct option is B) Given, S n=5n−n 2 S 1=a 1=5(1)−1 2=4 S 2=5(2)−2 2=6 a 2=S 2−a 1=6−4=2 d=a 2−a 1=2−4=−2 a n=a+(n−1)d a n=4+(n−1)(−2) ∴a n=6−2n Was this answer helpful? 0 0 Similar questions Find
In an ap sum of first n terms is 3n 2/2
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WebApr 13, 2024 · If the sum of the first n terms of an arithmetic sequence is 3n^2 + n, and the first term is 1, what is the common difference of the sequence? Toggle navigation. Home; Ask A Question; Answer Questions; Users; Support/FAQ; Register; Login; Math Problem. yaspal2510. Question. If the sum of the first n terms of an arithmetic sequence is 3n^2 + … WebApr 8, 2024 · Let the sum of n terms be given by Sn. so. Sn = 3n²/2+ 5n/2. S1 = 3(1)²/2 + 5(1)/2 = 3/2+5/2 => 4. so 1st term is 4 say 'a' Now. S2 = 3(2)²/2 + 5(2)/2 = 6+5 => 11. Now …
WebAug 28, 2024 · Let the sum of n terms be given by Sn so Sn = 3n²/2+ 5n/2 S1 = 3 (1)²/2 + 5 (1)/2 = 3/2+5/2 => 4 so 1st term is 4 say 'a' Now S2 = 3 (2)²/2 + 5 (2)/2 = 6+5 => 11 Now a2 … WebSep 15, 2024 · Solution: We can use our concept of AP here to solve the problem as follows: Step 1: Calculate the first number divisible by 3 in the given range: 20 = 3 × 6 + 2 a = 20 + (3 - remainder) a = 20 + (3 - 2) a = 21. Step 2: Calculate the Last number (nth) in the given range:-.
WebThe Sum of the First N Term Sofa an Ap is `( (3n^2) /2 +(5n) /2)`. Find Its Nth Term and the 25th Term . CBSE English Medium Class 10. Question Papers 939. Textbook Solutions 33590. MCQ Online Mock Tests 12. Important Solutions 4010. Question Bank Solutions 26519. Concept Notes & Videos 213. WebLet the sum of n terms be given by SnsoSn = 3n²/2+5n/2S1 = 3(1)²/2+5(1)/2= 3/2+5/2= 4So 1st term is 4 say aNowS2 = 3(2)²/2+5(2)/2= 6+5= 11Now a2 =S2−a1=> a2 =11−4= 7Now …
WebMar 30, 2024 · Given Sn = 2n2 + 3n Taking n = 1 S1 = 2 12 + 3 1 = 2 + 3 = 5 So, Sum of first term of AP is 5 But sum of first term will be the first term So, First term = a = 5 Taking n = …
WebAs per the formula of n th term of ap, the first term can be found by using a = T n - (n - 1)d. ☛ Related Topics: n th Term of AP Calculator; Sum of AP Calculator; Arithmetic and Geometric Progressions . nth Term of AP Examples. Example 1: Find the 20 th term of an AP whose 3 rd term is 5 and 7 th term is 13? fitinn rathausWebIf the sum of the first n terms of an A.P. is (1/2) [3n2 + 7n], then find its nth term. Hence write its 20th term. arithmetic progression cbse class-10 1 Answer +4 votes answered Sep 30, 2024 by KajalAgarwal (45.2k points) selected Oct 1, 2024 by Vikash Kumar Hence, a2 = 62 ← Prev Question Next Question → Find MCQs & Mock Test can horses lie downWebIn an AP, the sum of first n terms is 3n^22 + 13n2 Find the 25th term. Class 11 >> Applied Mathematics >> Sequences and series >> Arithmetic progression >> In an AP, the sum of … fitinn personal trainerWebDec 19, 2024 · (iii) Sum of n terms of an AP is always quadratic in ‘n’ Example: S n = 2n 2 + 3n. Example: S n = n/4 (n + 1) we can find ‘d’ also from S n. d = 2 (coefficient of n 2) for eg. : 2n 2 + 3n, d = 2 (2) = 4 Verification: S n = 2n 2 + 3n at n = 1, S 1 = 2 + 3 = 5 = first term at n = 2, S 2 = 2 (2) 2 + 3 (2) = 8 + 6 = 14 ≠ second term can horses live in a forestWebMar 30, 2024 · There are 2 AP s with different first term and common difference For the first AP Let first term be a common difference be d Sum of n term = Sn = /2 (2a + (n 1)d) & nth term = an = a + (n 1)d Similarly for second AP Let first term = A common difference = D Sn = /2 (2A + (n 1)D) & nth term = An = A + (n 1)D We need to find ratio of 12th term i.e. … can horses live aloneWebIt is given that sum of the first n terms of an A.P. is 3n 2 + 6n. ∴ First term = a = S 1 = 3 (1) 2 + 6 (1) = 9. Sum of first two terms = S 2 = 3 (2) 2 + 6 (2) = 24. ∴ Second term = S 2 − S 1 = 24 − 9 = 15. ∴ Common difference = d = Second term − First term = 15 − 9 = 6 Also, n th term = a n = a + (n − 1)d ⇒ a n = 9 + (n − 1)6 ⇒ a n = 9 + 6n − 6 can horses live in the cityWeb4 rows · 2 × Sum = n×(a+l) ⇒ Sum = n/2(a+l) Substituting the value of l in the previous equation, ... can horses live in hot weather